0=-16t^2+80t+60

Solution for 0=-16t^2+80t+60 equation:

0=-16t^2+80t+60

We move all terms to the left:

0-(-16t^2+80t+60)=0

We add all the numbers together, and all the variables

-(-16t^2+80t+60)=0

We get rid of parentheses

16t^2-80t-60=0

a = 16; b = -80; c = -60;
Δ = b2-4ac
Δ = -802-4·16·(-60)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-32\sqrt{10}}{2*16}=\frac{80-32\sqrt{10}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+32\sqrt{10}}{2*16}=\frac{80+32\sqrt{10}}{32}
$